-k^2-7k-6=0

Solution for -k^2-7k-6=0 equation:

-k^2-7k-6=0

We add all the numbers together, and all the variables

-1k^2-7k-6=0

a = -1; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·(-1)·(-6)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*-1}=\frac{2}{-2}
=-1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*-1}=\frac{12}{-2}
=-6
$